6(2y-3)+42=180

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Solution for 6(2y-3)+42=180 equation: 



6(2y-3)+42=180

We move all terms to the left:

6(2y-3)+42-(180)=0

We add all the numbers together, and all the variables

6(2y-3)-138=0

We multiply parentheses

12y-18-138=0

We add all the numbers together, and all the variables

12y-156=0

We move all terms containing y to the left, all other terms to the right

12y=156

y=156/12

y=13

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