1/5y=32

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Solution for 1/5y=32 equation: 



1/5y=32

We move all terms to the left:

1/5y-(32)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



We multiply all the terms by the denominator


-32*5y+1=0

Wy multiply elements

-160y+1=0

We move all terms containing y to the left, all other terms to the right

-160y=-1

y=-1/-160

y=1/160

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