5-(4x+3)=7-2(5-3x)

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Solution for 5-(4x+3)=7-2(5-3x) equation: 



5-(4x+3)=7-2(5-3x)

We move all terms to the left:

5-(4x+3)-(7-2(5-3x))=0

We add all the numbers together, and all the variables

-(4x+3)-(7-2(-3x+5))+5=0

We get rid of parentheses

-4x-(7-2(-3x+5))-3+5=0



We calculate terms in parentheses: -(7-2(-3x+5)), so:

7-2(-3x+5)

determiningTheFunctionDomain
-2(-3x+5)+7

We multiply parentheses

6x-10+7

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

-4x-(6x-3)+2=0

We get rid of parentheses

-4x-6x+3+2=0

We add all the numbers together, and all the variables

-10x+5=0

We move all terms containing x to the left, all other terms to the right

-10x=-5

x=-5/-10

x=1/2

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