7b+3+-4b=3-3(b+4)

Solution for 7b+3+-4b=3-3(b+4) equation:

7b+3+-4b=3-3(b+4)

We move all terms to the left:

7b+3+-4b-(3-3(b+4))=0

We add all the numbers together, and all the variables

3b-(3-3(b+4))=0


We calculate terms in parentheses: -(3-3(b+4)), so:

3-3(b+4)

determiningTheFunctionDomain
-3(b+4)+3

We multiply parentheses

-3b-12+3

We add all the numbers together, and all the variables

-3b-9

Back to the equation:

-(-3b-9)


We get rid of parentheses

3b+3b+9=0

We add all the numbers together, and all the variables

6b+9=0

We move all terms containing b to the left, all other terms to the right

6b=-9

b=-9/6

b=-1+1/2