7(x-6)+22=2(x-5)

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Solution for 7(x-6)+22=2(x-5) equation: 



7(x-6)+22=2(x-5)

We move all terms to the left:

7(x-6)+22-(2(x-5))=0

We multiply parentheses

7x-(2(x-5))-42+22=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

7x-(2x-10)-20=0

We get rid of parentheses

7x-2x+10-20=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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