7a+7-6=2(6+3a)+2(a-5)

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Solution for 7a+7-6=2(6+3a)+2(a-5) equation: 



7a+7-6=2(6+3a)+2(a-5)

We move all terms to the left:

7a+7-6-(2(6+3a)+2(a-5))=0

We add all the numbers together, and all the variables

7a-(2(3a+6)+2(a-5))+7-6=0

We add all the numbers together, and all the variables

7a-(2(3a+6)+2(a-5))+1=0



We calculate terms in parentheses: -(2(3a+6)+2(a-5)), so:

2(3a+6)+2(a-5)

We multiply parentheses

6a+2a+12-10

We add all the numbers together, and all the variables

8a+2

Back to the equation:

-(8a+2)



We get rid of parentheses

7a-8a-2+1=0

We add all the numbers together, and all the variables

-1a-1=0

We move all terms containing a to the left, all other terms to the right

-a=1

a=1/-1

a=-1

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