6(2x-9)=20-4(5x-3)

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Solution for 6(2x-9)=20-4(5x-3) equation: 



6(2x-9)=20-4(5x-3)

We move all terms to the left:

6(2x-9)-(20-4(5x-3))=0

We multiply parentheses

12x-(20-4(5x-3))-54=0



We calculate terms in parentheses: -(20-4(5x-3)), so:

20-4(5x-3)

determiningTheFunctionDomain
-4(5x-3)+20

We multiply parentheses

-20x+12+20

We add all the numbers together, and all the variables

-20x+32

Back to the equation:

-(-20x+32)



We get rid of parentheses

12x+20x-32-54=0

We add all the numbers together, and all the variables

32x-86=0

We move all terms containing x to the left, all other terms to the right

32x=86

x=86/32

x=2+11/16

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