23=1/3(2x+9)+12

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Solution for 23=1/3(2x+9)+12 equation: 



23=1/3(2x+9)+12

We move all terms to the left:

23-(1/3(2x+9)+12)=0



Domain of the equation: 3(2x+9)+12)!=0

x∈R



We multiply all the terms by the denominator


-(1+23*3(2x+9)+12)=0



We calculate terms in parentheses: -(1+23*3(2x+9)+12), so:

1+23*3(2x+9)+12

determiningTheFunctionDomain
23*3(2x+9)+1+12

We add all the numbers together, and all the variables

23*3(2x+9)+13

Wy multiply elements

69x(2+13

Back to the equation:

-(69x(2+13)



We add all the numbers together, and all the variables

-(69x15=0

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