7=(10/2x+3)+5

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Solution for 7=(10/2x+3)+5 equation: 



7=(10/2x+3)+5

We move all terms to the left:

7-((10/2x+3)+5)=0



Domain of the equation: 2x+3)+5)!=0

x∈R



We multiply all the terms by the denominator


-((10+7*2x+3)+5)=0



We calculate terms in parentheses: -((10+7*2x+3)+5), so:

(10+7*2x+3)+5

We add all the numbers together, and all the variables

(7*2x+13)+5

We get rid of parentheses

7*2x+13+5

We add all the numbers together, and all the variables

7*2x+18

Wy multiply elements

14x+18

Back to the equation:

-(14x+18)



We get rid of parentheses

-14x-18=0

We move all terms containing x to the left, all other terms to the right

-14x=18

x=18/-14

x=-1+2/7

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