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7x(3x+11)=6-5-3x)
We move all terms to the left:
7x(3x+11)-(6-5-3x))=0
We add all the numbers together, and all the variables
7x(3x+11)-(-3x+1))=0
We multiply parentheses
21x^2+77x-(-3x+1))=0
We get rid of parentheses
21x^2+77x+3x-1)=0
We add all the numbers together, and all the variables
21x^2+80x=0
a = 21; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·21·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*21}=\frac{-160}{42} =-3+17/21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*21}=\frac{0}{42} =0 $
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