3(b-2)=4(b-3)

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Solution for 3(b-2)=4(b-3) equation: 



3(b-2)=4(b-3)

We move all terms to the left:

3(b-2)-(4(b-3))=0

We multiply parentheses

3b-(4(b-3))-6=0



We calculate terms in parentheses: -(4(b-3)), so:

4(b-3)

We multiply parentheses

4b-12

Back to the equation:

-(4b-12)



We get rid of parentheses

3b-4b+12-6=0

We add all the numbers together, and all the variables

-1b+6=0

We move all terms containing b to the left, all other terms to the right

-b=-6

b=-6/-1

b=+6

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