72+3(x+2x2)=2(6x+3x2)

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Solution for 72+3(x+2x2)=2(6x+3x2) equation: 



72+3(x+2x^2)=2(6x+3x^2)

We move all terms to the left:

72+3(x+2x^2)-(2(6x+3x^2))=0

We multiply parentheses

6x^2-(2(6x+3x^2))+3x+72=0



We calculate terms in parentheses: -(2(6x+3x^2)), so:

2(6x+3x^2)

We multiply parentheses

6x^2+12x

Back to the equation:

-(6x^2+12x)



We add all the numbers together, and all the variables

6x^2+3x-(6x^2+12x)+72=0

We get rid of parentheses

6x^2-6x^2+3x-12x+72=0

We add all the numbers together, and all the variables

-9x+72=0

We move all terms containing x to the left, all other terms to the right

-9x=-72

x=-72/-9

x=+8

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