(6x+2)+5x+(3x-1)=141

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Solution for (6x+2)+5x+(3x-1)=141 equation: 



(6x+2)+5x+(3x-1)=141

We move all terms to the left:

(6x+2)+5x+(3x-1)-(141)=0

We add all the numbers together, and all the variables

5x+(6x+2)+(3x-1)-141=0

We get rid of parentheses

5x+6x+3x+2-1-141=0

We add all the numbers together, and all the variables

14x-140=0

We move all terms containing x to the left, all other terms to the right

14x=140

x=140/14

x=10

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