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7/5x=x-1
We move all terms to the left:
7/5x-(x-1)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
7/5x-x+1=0
We multiply all the terms by the denominator
-x*5x+1*5x+7=0
Wy multiply elements
-5x^2+5x+7=0
a = -5; b = 5; c = +7;
Δ = b2-4ac
Δ = 52-4·(-5)·7
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{165}}{2*-5}=\frac{-5-\sqrt{165}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{165}}{2*-5}=\frac{-5+\sqrt{165}}{-10} $
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