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1/2x=5x+12
We move all terms to the left:
1/2x-(5x+12)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-5x-12=0
We multiply all the terms by the denominator
-5x*2x-12*2x+1=0
Wy multiply elements
-10x^2-24x+1=0
a = -10; b = -24; c = +1;
Δ = b2-4ac
Δ = -242-4·(-10)·1
Δ = 616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{616}=\sqrt{4*154}=\sqrt{4}*\sqrt{154}=2\sqrt{154}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{154}}{2*-10}=\frac{24-2\sqrt{154}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{154}}{2*-10}=\frac{24+2\sqrt{154}}{-20} $
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