8(4x-1)+12x=11(2x+-6)

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Solution for 8(4x-1)+12x=11(2x+-6) equation: 



8(4x-1)+12x=11(2x+-6)

We move all terms to the left:

8(4x-1)+12x-(11(2x+-6))=0

We add all the numbers together, and all the variables

8(4x-1)+12x-(11(2x-6))=0

We add all the numbers together, and all the variables

12x+8(4x-1)-(11(2x-6))=0

We multiply parentheses

12x+32x-(11(2x-6))-8=0



We calculate terms in parentheses: -(11(2x-6)), so:

11(2x-6)

We multiply parentheses

22x-66

Back to the equation:

-(22x-66)



We add all the numbers together, and all the variables

44x-(22x-66)-8=0

We get rid of parentheses

44x-22x+66-8=0

We add all the numbers together, and all the variables

22x+58=0

We move all terms containing x to the left, all other terms to the right

22x=-58

x=-58/22

x=-2+7/11

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