5(x-6)+20-5x=4(2x-5)+10-5x

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Solution for 5(x-6)+20-5x=4(2x-5)+10-5x equation: 



5(x-6)+20-5x=4(2x-5)+10-5x

We move all terms to the left:

5(x-6)+20-5x-(4(2x-5)+10-5x)=0

We add all the numbers together, and all the variables

-5x+5(x-6)-(4(2x-5)+10-5x)+20=0

We multiply parentheses

-5x+5x-(4(2x-5)+10-5x)-30+20=0



We calculate terms in parentheses: -(4(2x-5)+10-5x), so:

4(2x-5)+10-5x

determiningTheFunctionDomain
4(2x-5)-5x+10

We add all the numbers together, and all the variables

-5x+4(2x-5)+10

We multiply parentheses

-5x+8x-20+10

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We add all the numbers together, and all the variables

-(3x-10)-10=0

We get rid of parentheses

-3x+10-10=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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