-6(3r-2)=-8r+40

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Solution for -6(3r-2)=-8r+40 equation: 



-6(3r-2)=-8r+40

We move all terms to the left:

-6(3r-2)-(-8r+40)=0

We multiply parentheses

-18r-(-8r+40)+12=0

We get rid of parentheses

-18r+8r-40+12=0

We add all the numbers together, and all the variables

-10r-28=0

We move all terms containing r to the left, all other terms to the right

-10r=28

r=28/-10

r=-2+4/5

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