7/5x+4/10x=48/15

Solution for 7/5x+4/10x=48/15 equation:

7/5x+4/10x=48/15

We move all terms to the left:

7/5x+4/10x-(48/15)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We add all the numbers together, and all the variables

7/5x+4/10x-(+48/15)=0

We get rid of parentheses

7/5x+4/10x-48/15=0

We calculate fractions


(-2400x^2)/750x^2+1050x/750x^2+300x/750x^2=0

We multiply all the terms by the denominator


(-2400x^2)+1050x+300x=0

We add all the numbers together, and all the variables

(-2400x^2)+1350x=0

We get rid of parentheses

-2400x^2+1350x=0

a = -2400; b = 1350; c = 0;
Δ = b2-4ac
Δ = 13502-4·(-2400)·0
Δ = 1822500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1822500}=1350$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1350)-1350}{2*-2400}=\frac{-2700}{-4800}
=9/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1350)+1350}{2*-2400}=\frac{0}{-4800}
=0
$