7/2x+8=13/4x+10

Solution for 7/2x+8=13/4x+10 equation:

7/2x+8=13/4x+10

We move all terms to the left:

7/2x+8-(13/4x+10)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+10)!=0

x∈R


We get rid of parentheses

7/2x-13/4x-10+8=0

We calculate fractions


28x/8x^2+(-26x)/8x^2-10+8=0

We add all the numbers together, and all the variables

28x/8x^2+(-26x)/8x^2-2=0

We multiply all the terms by the denominator


28x+(-26x)-2*8x^2=0

Wy multiply elements

-16x^2+28x+(-26x)=0

We get rid of parentheses

-16x^2+28x-26x=0

We add all the numbers together, and all the variables

-16x^2+2x=0

a = -16; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-16)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-16}=\frac{-4}{-32}
=1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-16}=\frac{0}{-32}
=0
$