5(y-1)=3(y-5)-(1-3y)

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Solution for 5(y-1)=3(y-5)-(1-3y) equation: 



5(y-1)=3(y-5)-(1-3y)

We move all terms to the left:

5(y-1)-(3(y-5)-(1-3y))=0

We add all the numbers together, and all the variables

5(y-1)-(3(y-5)-(-3y+1))=0

We multiply parentheses

5y-(3(y-5)-(-3y+1))-5=0



We calculate terms in parentheses: -(3(y-5)-(-3y+1)), so:

3(y-5)-(-3y+1)

We multiply parentheses

3y-(-3y+1)-15

We get rid of parentheses

3y+3y-1-15

We add all the numbers together, and all the variables

6y-16

Back to the equation:

-(6y-16)



We get rid of parentheses

5y-6y+16-5=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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