4(2z-8)=7z+10

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Solution for 4(2z-8)=7z+10 equation: 



4(2z-8)=7z+10

We move all terms to the left:

4(2z-8)-(7z+10)=0

We multiply parentheses

8z-(7z+10)-32=0

We get rid of parentheses

8z-7z-10-32=0

We add all the numbers together, and all the variables

z-42=0

We move all terms containing z to the left, all other terms to the right

z=42

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