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7-((2x+9)+(6x-3))=2x-9
We move all terms to the left:
7-((2x+9)+(6x-3))-(2x-9)=0
We get rid of parentheses
-((2x+9)+(6x-3))-2x+9+7=0
We calculate terms in parentheses: -((2x+9)+(6x-3)), so:We add all the numbers together, and all the variables
(2x+9)+(6x-3)
We get rid of parentheses
2x+6x+9-3
We add all the numbers together, and all the variables
8x+6
Back to the equation:
-(8x+6)
-2x-(8x+6)+16=0
We get rid of parentheses
-2x-8x-6+16=0
We add all the numbers together, and all the variables
-10x+10=0
We move all terms containing x to the left, all other terms to the right
-10x=-10
x=-10/-10
x=1
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