10x*x=39

Solution for 10x*x=39 equation:

10x*x=39

We move all terms to the left:

10x*x-(39)=0

Wy multiply elements

10x^2-39=0

a = 10; b = 0; c = -39;
Δ = b2-4ac
Δ = 02-4·10·(-39)
Δ = 1560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1560}=\sqrt{4*390}=\sqrt{4}*\sqrt{390}=2\sqrt{390}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{390}}{2*10}=\frac{0-2\sqrt{390}}{20}
=-\frac{2\sqrt{390}}{20}
=-\frac{\sqrt{390}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{390}}{2*10}=\frac{0+2\sqrt{390}}{20}
=\frac{2\sqrt{390}}{20}
=\frac{\sqrt{390}}{10}
$