4(2x-7)-2=6(x-5)+10

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Solution for 4(2x-7)-2=6(x-5)+10 equation: 



4(2x-7)-2=6(x-5)+10

We move all terms to the left:

4(2x-7)-2-(6(x-5)+10)=0

We multiply parentheses

8x-(6(x-5)+10)-28-2=0



We calculate terms in parentheses: -(6(x-5)+10), so:

6(x-5)+10

We multiply parentheses

6x-30+10

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We add all the numbers together, and all the variables

8x-(6x-20)-30=0

We get rid of parentheses

8x-6x+20-30=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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