7+3(4x-4)=5-3(2x+1)

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Solution for 7+3(4x-4)=5-3(2x+1) equation: 



7+3(4x-4)=5-3(2x+1)

We move all terms to the left:

7+3(4x-4)-(5-3(2x+1))=0

We multiply parentheses

12x-(5-3(2x+1))-12+7=0



We calculate terms in parentheses: -(5-3(2x+1)), so:

5-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+5

We multiply parentheses

-6x-3+5

We add all the numbers together, and all the variables

-6x+2

Back to the equation:

-(-6x+2)



We add all the numbers together, and all the variables

12x-(-6x+2)-5=0

We get rid of parentheses

12x+6x-2-5=0

We add all the numbers together, and all the variables

18x-7=0

We move all terms containing x to the left, all other terms to the right

18x=7

x=7/18

x=7/18

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