(1/4)x+12=(3/4)x-4

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Solution for (1/4)x+12=(3/4)x-4 equation: 



(1/4)x+12=(3/4)x-4

We move all terms to the left:

(1/4)x+12-((3/4)x-4)=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4)x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)x-((+3/4)x-4)+12=0

We multiply parentheses

x^2-((+3/4)x-4)+12=0

We multiply all the terms by the denominator


x^2*4)x-4)-((+12*4)x-4)+3=0

We add all the numbers together, and all the variables

x^2*4)x-4)-(48x-4)+3=0

Wy multiply elements

4x^3=0

We do not support expression: x^3

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