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(1/4)n+12=(3/4)n-4
We move all terms to the left:
(1/4)n+12-((3/4)n-4)=0
Domain of the equation: 4)n!=0
n!=0/1
n!=0
n∈R
Domain of the equation: 4)n-4)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
(+1/4)n-((+3/4)n-4)+12=0
We multiply parentheses
n^2-((+3/4)n-4)+12=0
We multiply all the terms by the denominator
n^2*4)n-4)-((+12*4)n-4)+3=0
We add all the numbers together, and all the variables
n^2*4)n-4)-(48n-4)+3=0
Wy multiply elements
4n^3=0
We do not support enpression: n^3
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