7+2(3y-6)=-2(8y-1)+8y

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Solution for 7+2(3y-6)=-2(8y-1)+8y equation: 



7+2(3y-6)=-2(8y-1)+8y

We move all terms to the left:

7+2(3y-6)-(-2(8y-1)+8y)=0

We multiply parentheses

6y-(-2(8y-1)+8y)-12+7=0



We calculate terms in parentheses: -(-2(8y-1)+8y), so:

-2(8y-1)+8y

We add all the numbers together, and all the variables

8y-2(8y-1)

We multiply parentheses

8y-16y+2

We add all the numbers together, and all the variables

-8y+2

Back to the equation:

-(-8y+2)



We add all the numbers together, and all the variables

6y-(-8y+2)-5=0

We get rid of parentheses

6y+8y-2-5=0

We add all the numbers together, and all the variables

14y-7=0

We move all terms containing y to the left, all other terms to the right

14y=7

y=7/14

y=1/2

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