3w-1+5(2w+2)=-3(w+1)

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Solution for 3w-1+5(2w+2)=-3(w+1) equation: 



3w-1+5(2w+2)=-3(w+1)

We move all terms to the left:

3w-1+5(2w+2)-(-3(w+1))=0

We multiply parentheses

3w+10w-(-3(w+1))+10-1=0



We calculate terms in parentheses: -(-3(w+1)), so:

-3(w+1)

We multiply parentheses

-3w-3

Back to the equation:

-(-3w-3)



We add all the numbers together, and all the variables

13w-(-3w-3)+9=0

We get rid of parentheses

13w+3w+3+9=0

We add all the numbers together, and all the variables

16w+12=0

We move all terms containing w to the left, all other terms to the right

16w=-12

w=-12/16

w=-3/4

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