-3(3u-5)+3u=7+4(3u-1)

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Solution for -3(3u-5)+3u=7+4(3u-1) equation: 



-3(3u-5)+3u=7+4(3u-1)

We move all terms to the left:

-3(3u-5)+3u-(7+4(3u-1))=0

We add all the numbers together, and all the variables

3u-3(3u-5)-(7+4(3u-1))=0

We multiply parentheses

3u-9u-(7+4(3u-1))+15=0



We calculate terms in parentheses: -(7+4(3u-1)), so:

7+4(3u-1)

determiningTheFunctionDomain
4(3u-1)+7

We multiply parentheses

12u-4+7

We add all the numbers together, and all the variables

12u+3

Back to the equation:

-(12u+3)



We add all the numbers together, and all the variables

-6u-(12u+3)+15=0

We get rid of parentheses

-6u-12u-3+15=0

We add all the numbers together, and all the variables

-18u+12=0

We move all terms containing u to the left, all other terms to the right

-18u=-12

u=-12/-18

u=2/3

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