7+0.32y=3/5y

Solution for 7+0.32y=3/5y equation:

7+0.32y=3/5y

We move all terms to the left:

7+0.32y-(3/5y)=0


Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

0.32y-(+3/5y)+7=0

We get rid of parentheses

0.32y-3/5y+7=0

We multiply all the terms by the denominator


(0.32y)*5y+7*5y-3=0

We add all the numbers together, and all the variables

(+0.32y)*5y+7*5y-3=0

We multiply parentheses

0y^2+7*5y-3=0

Wy multiply elements

0y^2+35y-3=0

We add all the numbers together, and all the variables

y^2+35y-3=0

a = 1; b = 35; c = -3;
Δ = b2-4ac
Δ = 352-4·1·(-3)
Δ = 1237
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1237}}{2*1}=\frac{-35-\sqrt{1237}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1237}}{2*1}=\frac{-35+\sqrt{1237}}{2}
$