10p2=1210

Solution for 10p2=1210 equation:

10p^2=1210

We move all terms to the left:

10p^2-(1210)=0

a = 10; b = 0; c = -1210;
Δ = b2-4ac
Δ = 02-4·10·(-1210)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-220}{2*10}=\frac{-220}{20}
=-11
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+220}{2*10}=\frac{220}{20}
=11
$