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m2-10=141.29
We move all terms to the left:
m2-10-(141.29)=0
We add all the numbers together, and all the variables
m^2-151.29=0
a = 1; b = 0; c = -151.29;
Δ = b2-4ac
Δ = 02-4·1·(-151.29)
Δ = 605.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{605.16}}{2*1}=\frac{0-\sqrt{605.16}}{2} =-\frac{\sqrt{}}{2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{605.16}}{2*1}=\frac{0+\sqrt{605.16}}{2} =\frac{\sqrt{}}{2} $
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