7(y-2)+3(4y-5)=6

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Solution for 7(y-2)+3(4y-5)=6 equation: 



7(y-2)+3(4y-5)=6

We move all terms to the left:

7(y-2)+3(4y-5)-(6)=0

We multiply parentheses

7y+12y-14-15-6=0

We add all the numbers together, and all the variables

19y-35=0

We move all terms containing y to the left, all other terms to the right

19y=35

y=35/19

y=1+16/19

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