2m+3(2-7)=4+5(m+2)

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Solution for 2m+3(2-7)=4+5(m+2) equation: 



2m+3(2-7)=4+5(m+2)

We move all terms to the left:

2m+3(2-7)-(4+5(m+2))=0

We add all the numbers together, and all the variables

2m-(4+5(m+2))+3(-5)=0

We add all the numbers together, and all the variables

2m-(4+5(m+2))-15=0



We calculate terms in parentheses: -(4+5(m+2)), so:

4+5(m+2)

determiningTheFunctionDomain
5(m+2)+4

We multiply parentheses

5m+10+4

We add all the numbers together, and all the variables

5m+14

Back to the equation:

-(5m+14)



We get rid of parentheses

2m-5m-14-15=0

We add all the numbers together, and all the variables

-3m-29=0

We move all terms containing m to the left, all other terms to the right

-3m=29

m=29/-3

m=-9+2/3

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