6(a+2)=a-(10-a)

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Solution for 6(a+2)=a-(10-a) equation: 



6(a+2)=a-(10-a)

We move all terms to the left:

6(a+2)-(a-(10-a))=0

We add all the numbers together, and all the variables

6(a+2)-(a-(-1a+10))=0

We multiply parentheses

6a-(a-(-1a+10))+12=0



We calculate terms in parentheses: -(a-(-1a+10)), so:

a-(-1a+10)

We get rid of parentheses

a+1a-10

We add all the numbers together, and all the variables

2a-10

Back to the equation:

-(2a-10)



We get rid of parentheses

6a-2a+10+12=0

We add all the numbers together, and all the variables

4a+22=0

We move all terms containing a to the left, all other terms to the right

4a=-22

a=-22/4

a=-5+1/2

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