2k-7(k+3)=8-(3k-4)

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Solution for 2k-7(k+3)=8-(3k-4) equation: 



2k-7(k+3)=8-(3k-4)

We move all terms to the left:

2k-7(k+3)-(8-(3k-4))=0

We multiply parentheses

2k-7k-(8-(3k-4))-21=0



We calculate terms in parentheses: -(8-(3k-4)), so:

8-(3k-4)

determiningTheFunctionDomain
-(3k-4)+8

We get rid of parentheses

-3k+4+8

We add all the numbers together, and all the variables

-3k+12

Back to the equation:

-(-3k+12)



We add all the numbers together, and all the variables

-5k-(-3k+12)-21=0

We get rid of parentheses

-5k+3k-12-21=0

We add all the numbers together, and all the variables

-2k-33=0

We move all terms containing k to the left, all other terms to the right

-2k=33

k=33/-2

k=-16+1/2

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