7(y+2)=-4(2y-2)+6y

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Solution for 7(y+2)=-4(2y-2)+6y equation:



7(y+2)=-4(2y-2)+6y
We move all terms to the left:
7(y+2)-(-4(2y-2)+6y)=0
We multiply parentheses
7y-(-4(2y-2)+6y)+14=0
We calculate terms in parentheses: -(-4(2y-2)+6y), so:
-4(2y-2)+6y
We add all the numbers together, and all the variables
6y-4(2y-2)
We multiply parentheses
6y-8y+8
We add all the numbers together, and all the variables
-2y+8
Back to the equation:
-(-2y+8)
We get rid of parentheses
7y+2y-8+14=0
We add all the numbers together, and all the variables
9y+6=0
We move all terms containing y to the left, all other terms to the right
9y=-6
y=-6/9
y=-2/3

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