7(x-8)=6(1-4x)+8x

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Solution for 7(x-8)=6(1-4x)+8x equation: 



7(x-8)=6(1-4x)+8x

We move all terms to the left:

7(x-8)-(6(1-4x)+8x)=0

We add all the numbers together, and all the variables

7(x-8)-(6(-4x+1)+8x)=0

We multiply parentheses

7x-(6(-4x+1)+8x)-56=0



We calculate terms in parentheses: -(6(-4x+1)+8x), so:

6(-4x+1)+8x

We add all the numbers together, and all the variables

8x+6(-4x+1)

We multiply parentheses

8x-24x+6

We add all the numbers together, and all the variables

-16x+6

Back to the equation:

-(-16x+6)



We get rid of parentheses

7x+16x-6-56=0

We add all the numbers together, and all the variables

23x-62=0

We move all terms containing x to the left, all other terms to the right

23x=62

x=62/23

x=2+16/23

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