7+3b=3(1+4b)-7b

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Solution for 7+3b=3(1+4b)-7b equation:



7+3b=3(1+4b)-7b
We move all terms to the left:
7+3b-(3(1+4b)-7b)=0
We add all the numbers together, and all the variables
3b-(3(4b+1)-7b)+7=0
We calculate terms in parentheses: -(3(4b+1)-7b), so:
3(4b+1)-7b
We add all the numbers together, and all the variables
-7b+3(4b+1)
We multiply parentheses
-7b+12b+3
We add all the numbers together, and all the variables
5b+3
Back to the equation:
-(5b+3)
We get rid of parentheses
3b-5b-3+7=0
We add all the numbers together, and all the variables
-2b+4=0
We move all terms containing b to the left, all other terms to the right
-2b=-4
b=-4/-2
b=+2

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