w*3w=2w(w+2)

Solution for w*3w=2w(w+2) equation:

w*3w=2w(w+2)

We move all terms to the left:

w*3w-(2w(w+2))=0

Wy multiply elements

3w^2-(2w(w+2))=0


We calculate terms in parentheses: -(2w(w+2)), so:

2w(w+2)

We multiply parentheses

2w^2+4w

Back to the equation:

-(2w^2+4w)


We get rid of parentheses

3w^2-2w^2-4w=0

We add all the numbers together, and all the variables

w^2-4w=0

a = 1; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·1·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*1}=\frac{0}{2}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*1}=\frac{8}{2}
=4
$