7(x-8)+2=3-(x+1)

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Solution for 7(x-8)+2=3-(x+1) equation: 



7(x-8)+2=3-(x+1)

We move all terms to the left:

7(x-8)+2-(3-(x+1))=0

We multiply parentheses

7x-(3-(x+1))-56+2=0



We calculate terms in parentheses: -(3-(x+1)), so:

3-(x+1)

determiningTheFunctionDomain
-(x+1)+3

We get rid of parentheses

-x-1+3

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We add all the numbers together, and all the variables

7x-(-1x+2)-54=0

We get rid of parentheses

7x+1x-2-54=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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