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4/3x-10/4x-11=1
We move all terms to the left:
4/3x-10/4x-11-(1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
4/3x-10/4x-12=0
We calculate fractions
16x/12x^2+(-30x)/12x^2-12=0
We multiply all the terms by the denominator
16x+(-30x)-12*12x^2=0
Wy multiply elements
-144x^2+16x+(-30x)=0
We get rid of parentheses
-144x^2+16x-30x=0
We add all the numbers together, and all the variables
-144x^2-14x=0
a = -144; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-144)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-144}=\frac{0}{-288} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-144}=\frac{28}{-288} =-7/72 $
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