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9(v+3)-3v=2(3v+4)-9
We move all terms to the left:
9(v+3)-3v-(2(3v+4)-9)=0
We add all the numbers together, and all the variables
-3v+9(v+3)-(2(3v+4)-9)=0
We multiply parentheses
-3v+9v-(2(3v+4)-9)+27=0
We calculate terms in parentheses: -(2(3v+4)-9), so:We add all the numbers together, and all the variables
2(3v+4)-9
We multiply parentheses
6v+8-9
We add all the numbers together, and all the variables
6v-1
Back to the equation:
-(6v-1)
6v-(6v-1)+27=0
We get rid of parentheses
6v-6v+1+27=0
We add all the numbers together, and all the variables
28!=0
There is no solution for this equation
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