7(x-3)+1=-5(x+2)

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Solution for 7(x-3)+1=-5(x+2) equation: 



7(x-3)+1=-5(x+2)

We move all terms to the left:

7(x-3)+1-(-5(x+2))=0

We multiply parentheses

7x-(-5(x+2))-21+1=0



We calculate terms in parentheses: -(-5(x+2)), so:

-5(x+2)

We multiply parentheses

-5x-10

Back to the equation:

-(-5x-10)



We add all the numbers together, and all the variables

7x-(-5x-10)-20=0

We get rid of parentheses

7x+5x+10-20=0

We add all the numbers together, and all the variables

12x-10=0

We move all terms containing x to the left, all other terms to the right

12x=10

x=10/12

x=5/6

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