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7(x-2)-5(x-2)=2(x-4)
We move all terms to the left:
7(x-2)-5(x-2)-(2(x-4))=0
We multiply parentheses
7x-5x-(2(x-4))-14+10=0
We calculate terms in parentheses: -(2(x-4)), so:We add all the numbers together, and all the variables
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
2x-(2x-8)-4=0
We get rid of parentheses
2x-2x+8-4=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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