7/(4x)=3/(x-5)

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Solution for 7/(4x)=3/(x-5) equation:



7/(4x)=3/(x-5)
We move all terms to the left:
7/(4x)-(3/(x-5))=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: (x-5))!=0
x∈R
We calculate fractions
7x/(-16x^2)+(-(3*4x)/(-16x^2)=0
We calculate terms in parentheses: +(-(3*4x)/(-16x^2), so:
-(3*4x)/(-16x^2
We add all the numbers together, and all the variables
-(+3*4x)/(-16x^2
We multiply all the terms by the denominator
-(+3*4x)
We get rid of parentheses
-3*4x
Wy multiply elements
-12x
Back to the equation:
+(-12x)
We get rid of parentheses
7x/(-16x^2)-12x=0
We multiply all the terms by the denominator
-12x*(-16x^2)+7x=0
We multiply parentheses
192x^3+7x=0
We do not support expression: x^3

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