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7(x-2)-5(x-2)=(x-4)
We move all terms to the left:
7(x-2)-5(x-2)-((x-4))=0
We multiply parentheses
7x-5x-((x-4))-14+10=0
We calculate terms in parentheses: -((x-4)), so:We add all the numbers together, and all the variables
(x-4)
We get rid of parentheses
x-4
Back to the equation:
-(x-4)
2x-(x-4)-4=0
We get rid of parentheses
2x-x+4-4=0
We add all the numbers together, and all the variables
x=0
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