7(x+2)=34+3x

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Solution for 7(x+2)=34+3x equation: 



7(x+2)=34+3x

We move all terms to the left:

7(x+2)-(34+3x)=0

We add all the numbers together, and all the variables

7(x+2)-(3x+34)=0

We multiply parentheses

7x-(3x+34)+14=0

We get rid of parentheses

7x-3x-34+14=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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